Euler's equation
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Solution
\[\begin{aligned}
&\text { Let } f(x)=\frac{\cos x+i \sin x}{e^{i x}}\\\\
&\Rightarrow f^{\prime}(x)=\frac{\left(i \cos x-\sin x) e^{i x}-i e^{i x}(\cos x+i \sin x)\right.}{e^{2 i x}}\\\\
&=\frac{e^{i x}(i \cos x-\sin x-i \cos x+\sin x)}{e^{2 i x}}\\\\
&f^{\prime}(x)=0\\\\
&\Rightarrow f \text { is constant }\\\\
&\text { then } f(x)=f(0)\\\\
&\Leftrightarrow \frac{\cos x+i \sin x}{e^{i x}}=1\\\\
&\text { thus } e^{i x}=\cos x+i \sin x
\end{aligned}\]
\[e^{i x}=\cos x+i \sin x
\]
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