Home -> Solved problems -> e irrational number

Prove that \(e\) is an irrational number

Solution

The proof that e is an irrational number is one of the most beautiful results in mathematics. Euler’s constant 𝑒 e, which appears in exponential and logarithmic functions, cannot be expressed as a simple fraction. Understanding why this is true not only strengthens your knowledge of number theory but also deepens your appreciation of how mathematics uncovers patterns and structure. In this step-by-step explanation, we’ll follow the logic that shows why 𝑒 e cannot be written as a ratio of two integers. We’ll explore the series expansion of 𝑒 e, assume the opposite, and reach a contradiction — the core of mathematical reasoning.
To start, let’s expand the exponential function
\[\mathrm{e}^{x}=\sum_{k=0}^{\infty} \frac{x^{k}}{k !}\]
\[\Rightarrow e=\sum_{k=0}^{\infty} \frac{1}{k !}=1+\frac{1}{1 !}+\frac{1}{2 !}+\frac{1}{3 !}+\cdots\]
Assume that e is rational
\[e=\frac{m}{n}=1+\frac{1}{1 !}+\frac{1}{2 !}+\frac{1}{3 !}+\cdots \quad \text { for two coprime integers } m \text { and } n\]
\[\frac{m}{n}=1+\frac{1}{1 !}+\frac{1}{2 !}+\frac{1}{3 !}+\cdots+\frac{1}{n !}+\frac{1}{(n+1) !}+\frac{1}{(n+2) !}+\cdots\]
\[n ! \frac{m}{n}=n !+\frac{n !}{1 !}+\frac{n !}{2 !}+\frac{n !}{3 !}+\cdots+\frac{n !}{n !}+\frac{n !}{(n+1) !}+\frac{n !}{(n+2) !}+\cdots\]
\[\begin{aligned} &\mathrm{A}=n ! \frac{m}{n}=(n-1) ! m \in \mathbb{N} \\ &\mathrm{B}=n !+\frac{n !}{1 !}+\frac{n !}{2 !}+\frac{n !}{3 !}+\cdots+\frac{n !}{n !} \in \mathbb{N} \\ &\mathrm{C}=\frac{1}{n+1}+\frac{1}{(n+1)(n+2)}+\frac{1}{(n+1)(n+2)(n+3)}+\cdots \end{aligned}\]
\[\begin{gathered} \text { For } n \geqslant 1 \\ \frac{1}{n+1} \leqslant \frac{1}{2} \\ \frac{1}{(m+1)(n+2)}<\frac{1}{2^{2}} \\ \frac{1}{(n+1)(n+2)(n+3)}<\frac{1}{2^{3}} \\ \vdots \end{gathered}\]
\[\Rightarrow\mathrm{C}<\frac{1}{2}+\frac{1}{2^{2}}+\frac{1}{2^{3}}+\cdots=\left(\frac{1}{2}\right)\left(\frac{1}{1-\frac{1}{2}}\right)=1\]
\[0<c<1 \Rightarrow C \notin \mathbb{N}\]
\[\text { Therefore }\]
\[\huge \mathrm{e} \notin \mathbb{Q}\]
This proof not only confirms that 𝑒 e cannot be written as a fraction but also highlights how infinite series reveal deep truths about numbers. The concept of irrationality is central to understanding real numbers, calculus, and complex analysis.
The proof that e is irrational demonstrates how the combination of series, factorials, and logical reasoning uncovers the hidden structure of numbers. It’s a reminder that even simple mathematical constants like 𝑒 e carry profound and infinite complexity.
Home -> Solved problems -> e irrational number

Related Topics

Find the volume of the square pyramid as a function of \(a\) and \(H\) by slicing method.
Prove that \[\lim_{x \rightarrow 0}\frac{\sin x}{x}=1\]
Prove that
Calculate the half derivative of \(x\)
Prove Wallis Product Using Integration
Calculate the radius R
Calculate the volume of Torus using cylindrical shells
Find the derivative of exponential \(x\) from first principles
Calculate the sum of areas of the three squares
Find the equation of the curve formed by a cable suspended between two points at the same height
Solve the equation for real values of \(x\)
Solve the equation for \(x\epsilon\mathbb{R}\)
Determine the angle \(x\)
Calculate the following limit
Calculate the following limit
Calculate the integral
Challenging problem
Prove that
Prove that \(e\) is an irrational number
Home -> Solved problems -> e irrational number

Share the solution: e irrational number